How to calculate the molar concentration of acetic acid in a sample of vinegar?
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I have volume of vinegar = 10mL But the vinegar was diluted with distilled water (+ 90mL) so the new volume is 100mL Concentration of sodium hydroxide is 0.123M 3.66mL of NaOH was required to turn 25mL of the diluted solution pink/ purplish Anyone know what to do here?
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Answer:
Hi Adrien, Titration equation : CH3COOH + HO(-) = CH3COO(-) + H2O Concentration of the diluted vinegar solution : Ca x Va = Cb x Vb Ca = Cb x Vb / Va Ca = 0,123 x 3,66 / 10 Ca = 0,045 mol/L Concentration of vinegar : C2 = Ca C1 x V1 = C2 x V2 C1 = C2 x V2 / V1 C1 = 0,045 x 100 / 10 C1 = 0,45 mol/L
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