The empirical formula of a compound is C4H9 and its molecular mass is 114.26 amu.?
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The empirical formula of a compound is C4H9 and its molecular mass is 114.26 amu. Determine the compounds molecular formula.
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Answer:
The molar mass of C4H9 is (12*2)+(1*9) = 57 114/57 = 2. Because the molar mass of the real molecule doubles that of the empirical compound, you have to multiply the empirical formula by 2. C4H9 x 2 = C8H18 To see if that's right, find the molar mass of C8H18 (12*8) + (1*18) = 114 and it's the same So the compound's real molecular formula is C8H18
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