How to accept string with space in char array in C?

Henni's got the right idea. There is indeed no safe way to use gets(). But, you can use scanf safely. Few do (see the earlier answer) because it's a nusiance, but it can be done. In your program, use: printf("enter file name\n"); scanf("%19[^\n]",fl[i].file); printf("enter description\n"); scanf("%99[^\n]",fl[i].description); This is similar to James Bond's answer, except for the maximum lengths above. The %[list] scanf format is similar to %s, but only accept characters that are in the list. (If you want to include a ] as a valid character, make it first. %[]abc] accepts ']', 'a', 'b', or 'c', for example. The %[^list] format scans and accepts all characters that are NOT in the list. Both formats can (AND SHOULD) be prefixed with a maximum length. This does not include the trailing 0 string terminator, so it should be one less than the buffer size. Since char file[20] can hold up to a 19-character string, scan it with %19s or %19[list] or %19[^list]. Using the negative format %19[^\n] scans up to 19 characters that are not newline (\n) characters. That includes spaces, tabs, other control characters (except \n), and all printable characters. The nuisance factor is having to type the length in decimal in every scanf() format that reads into a particular array. If the array size changes, you must change the formats. For a large project, with lots of different places to scan into different string buffers, something like Henni's approach is correct. For small projects, I prefer getting the most use out of the safe part of the Standard C Library...which is most of it. Avoiding scanf() entirely because of buffer overruns caused by plain %s and %[] is throwing a lot of baby out with very little bathwater.

char x[80]; scanf("%[^\n]", x); // this read a line full of text which contains spaces also scanf("%[^g]", x); // this reads character till we enter g

To read a character array with spaces you better use 'gets' command rather than scanf for(i=0;i<10;i++) { printf("enter file name\n"); gets(fl[i].file); printf("enter description\n"); gets(fl[i].description); }

if you will use struct then you can not accept string with space in char array in C use this program for accept string with space in char array in C this program also works for accept string with lines. main() { char a,b,c,d; scanf("%c%c%c%c",&a,&b,&c,&d); printf("%c%c%c%c",a,b,c,d); } you will see the output i compiled it my input was a<space><space>f out put was a<space><space>f and if you want add for loop then add it by your self because i am lazy to type a big program lol