How many grams of NH3 can be produced from 4.84 mol of N2?

How many mol of wter is produced if 1276.9 mol of methane (CH4) is supplied?

• its for chemistry and i really dont understand any of it, so if you can help it will be much appreciated. there are also some other ones too, just do the ones you want. 1) C2H4 + 3 02 -> 2 CO2 + 2H2O if 3.93 X 10^17 mol of CO2 is produced, how many mol of O2 is required? 2) 8 HNO3 + 3 Cu -> 2 NO + 4 H2O + 3 C (NO3)2 if 34235.9 mol of nitric acid (HNO3) is supplied, how many mol of Cu (NO3)2 is produced? 3)4 C3H5O9N3 -> 12 CO2 + 6N2 +O2 +10 H2O if 1.3 X 10^7 grams of CO2 is produced, how many liters of N2 is also produced? 4)Fe2O3 +3CO -> 3CO2 + @fe 0.00963 mol of Fe2O3 will produce how many grams of CH3OH? 5) CO + 2H2 -> CH3OH 116.4 mol H2 will produce how many grams of CH3OH? 6) 2 C4H10 + 13 O2 -> 8 CO2 + 10 H2O 7900 mol of C4H10 will produce how many mole of CO2? 7)N2 + 3H2 -> 2NH3 7.300 X 10^5 mol of H2 will produce how many mol of NH3?

• Answer:

  These are all basic stoichiometry problems in chemistry. The fundamental concept is that the coefficients in a balanced equation can be used to relate moles of one thing to moles of any other. The balanced chemical equation is key, though. So, for the question in your title: Balanced Equation: CH4 + 2 O2 --> CO2 + 2 H2O 1276.9 mol CH4 X (2 mol H2O / 1 mol CH4) = 2553.8 mol H2O Now in many of your problems, you are either given a mass of something instead of moles, or you are asked for a mass of something. So, the general outline to follow is: 1. Convert mass of given into moles using its molar mass 2. Use coefficients in balanced equation to relate moles of one thing to moles of another 3. Convert moles of desired substance into grams using its molar mass. Now, it looks like you've mis-written some of your questions, since you ask for things that are not in the equation.(like #4). If #4 asked for "how many grams of CO2 will be formed", then it would be worked this way: 0.00963 mol Fe2O3 X (3 mol CO2 / 1 mol Fe2O3) = 0.02889 mol CO2 X 44.0 g/mol = 1.27 g CO2 On #3, it asks for a volume of N2. Since N2 is a gas, its volume depends on the temperature and pressure. Since those were not given, you must assume STP, at which 1 mole of any gas has a volume of 22.4 L. So, for that one: 1.3X10^7 g CO2 X (1 mol CO2 / 44.0 g CO2) = 2.95X10^5 mol CO2 X (6 mol N2 / 12 mol CO2) = 1.48X10^5 mol N2 X (22.4 L/ 1 mol) = 3.31X10^6 L N2 Hope this helps...