What's the output from this program using fork() and why?

C++ program using visual c++. Functions, call and ref statements with for loops, output two separate tabless?

• Need a little help please: i have been trying to complete this for a couple days but i get more and more confused everytime i try. When an object is falling because of gravity, the following formula can be used to determine the distance the object falls in a specific time period. D = ½ gt^2 The variables in the formula are as follows: d is the distance in meters, g is 9.8, and t is the amount of time in second that the object has been falling. Write a function named fallingDistance that accepts an object’s falling time (in seconds) as an argument. The function should return the distance, in meters, that the object has fallen during that time interval. Write a program that demonstrates the function by calling it in a loop that passes the values 1 though 10 as arguments, and displays the return value. *Additional to this problem my prof wants two functions that calculate the falling distance. function 1 passes arguments by value function 2 passes argument by reference outputs should be in form of a table whats confusing is the prof established that in the main it should resemeble like this: main() { for(--------------) call (by value) output for(---------------------) call (by reference) output my code so far call by ref works fine but call by value only works when i put double d as global but then it only comes back as 0's in the output. its not reading the equation. -------------------------- # include <iostream> # include <cmath> # include <string> using namespace std; void fallingDistance2(double &); double fallingDistance1(double); const double g = 9.8; int t; double d; int main() { cout<<"calculated by passby values.\n"; cout<<"Time \t\t Distance\n"; cout<<"-------------------\n"; for (t=1;t<=10;t++) { fallingDistance1(d); cout<<t<<"\t\t"<<d<<endl; } cout<<"calculated by reference values.\n"; cout<<"Time \t\t Distance\n"; cout<<"-------------------\n"; for (t=1;t<=10;t++) { fallingDistance2(d); cout<<t<<"\t\t"<<d<<endl; } return 0; } double fallingDistance1(double d) { d=0.5*9.8*t*t; return d; } void fallingDistance2(double &refd) { refd=0.5*9.8*t*t; }

• Answer:

  Both functions are wrong because you are supposed to pass the time and return the distance which you do neither. for pass by value you need to do this: double fallingDistance(int time){ return(0.5 * 9.8 * time * time); } and when you call it do this: d = fallingDistance(t); I'll let you figure out the other function you need.