Find height of a rocket given initial mass, velocity of ejecting fuel, final mass, and rate of burning fuel.?
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A rocket with a mass of 100kg burns fuel at a rate of 2 kg per second. the fuel leaves the rocket downward with a velocity of 500 meters per second until all the fuel is used. if the rocket's final mass is 1/4 of the initial mass, how high does the rocket go?
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Answer:
You might know the Newtons third law.Then,from the law rocket moves up due to the force exerted by the fuel on rocket and balances the gravitation of earth on rocket . now GMm*1/h*1/h=v*rate of burning of fuel.where M=mass of earth,Height of rocket,v=velocity of fuel. solve it and get h. I hope it helped.
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