What are the 3 basic functions of social work?

How Do Functions Work in Visual Basic 2010?

• I am trying to learn Visual Basic dot Net. I've learned about data types, how to declare variables and formatting dates. The text I'm reading has now moved on to Methods and discusses subroutines and Functions. I understand that Methods of the subroutine variety do not return a value while methods of the function variety do. I understand how to define and call a method. What I am totally stuck on is a particular function that is part of an exercise used in the text. This method returns a value therefore making it a function and stores it in a variable. In the subroutine that calls the function, another variable has been declared to hold the same result in the function. I know this because the MessageBox.Show method extracts the value from the variable in the subroutine and displays it. I don't understand how the value of a variable in the function was transferred to the variable in the subroutine for display by MessageBox.Show. I have attached the code below. Please explain this to me. It is driving me crazy. Public Class Form1 Private Sub Button1_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles Button1.Click 'Declare variable Dim dblArea As Double 'Calculate the area of a cirle with a radius of 100 dblArea = CalculateAreaFromRadius(100) 'Display the Results MessageBox.Show(dblArea.ToString, "Area of 100") End Sub 'CalculateAreaFromRadius-find the area of a circle Private Function CalculateAreaFromRadius(ByVal radius As Double) As Double 'Declare Variables Dim dblRadiusSquared As Double Dim dblResult As Double 'Square the Radius dblRadiusSquared = radius * radius 'Multiply it by PI dblResult = dblRadiusSquared * Math.PI 'Return the Result Return dblResult End Function End Class

• Answer:

  'Calculate the area of a cirle with a radius of 100 dblArea = CalculateAreaFromRadius(100) Here you are calling the function (CalculateAreaFromRadious) and passing it the value of 100. You can even write the name of a variable here. The variable dblArea will = the value which will be returned from the function. 'CalculateAreaFromRadius-find the area of a circle Private Function CalculateAreaFromRadius(ByVal --> radius <-- As Double) As Double The variable radius holds the number 100 which was passed to it. You do your calculations to the variable radius and return the variable dblResault to dblArea. dblResult = (radius * radius) * Math.PI Think this would work too, you dont need to have two variables.