How many grams of CO2 can be produced when 2 grams of Sodium Carbonate and 50 mL HCl Acid react?
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How many grams of Carbon Dioxide can be produced when 2 grams of Sodium Carbonate and 50 mL Hydrochloric Acid react? I don't know how to set up this equation, will someone please explain to me? I also have to find out how much CO2 is produced with Barium Carbonate, Calcium Carbonate, Lithium Carbonate, Potassium Carbonate and Strontium Carbonate as a substitute for Sodium Carbonate, but I can figure that out as long as someone helps me out with the equation! Thank you thank you!!!!!!
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Answer:
OK. I'll do the first one for y ou. The rest will be solved using exactly the same method. First we are going to assume that the reaction takes place at STP Step 1: Balanced equation. Na2CO3 + HCl -----------------> NaCl + H2O + CO2 Step 2: convert mass into moles. moles Na2CO3 = 2 g / 106.99 g/mol = 0.01869 moles of Na2CO3 Step 3: Use the mole ratio between Na2CO3 and CO2 to find the number of moles of CO2 expected to be produced. The mole ratio from the equation is 1 to 1. Therefore you would also expect 0.01869 moles of CO2 to be produced. Step 4: Convert the moles of CO2 into a volume. Vol of CO2 = 0.01869 moles x 22/4 L/mol = 0.4187 L or 42 mL (sig figs.) Repeat the above procedure with each of your other carbonates.
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