How are vector spaces viewed as universal algebras?

Vector spaces spanning Question?

  • Prove the following vector subspaces V and W of R^3 are equal: ...............( 1 ) ( 4 ) V=span ( 2 ) , ( 5 ) .............. ( 3 ) ( 6 ) ..................( 0 ) ( 1 ) ( 5 ) W= span ( 2 ) , ( 0 ) , ( 7 ) .................. ( 4 ) (-1 ) ( 9 ) Really need some help with this. Thanks in advance :)

  • Answer:

    To prove two vector subspaces are equal its sufficient to prove dim(V) =dim(W) dim(V) = 2 To prove dim(W) =2 Show that (5,7,9) is linear combination of (0,2,4) and (1,0,-1) w1 (0,2,4) + w2(1,0,-1) = (5,7,9) w2 = 5 ......................... 1 2w1 = 7 ......................... 2 4w1-w2 =9 .......................... 3 1 and 2 give 3 Hence proved. dim(W) =2 = dim(V)

Daniel at Yahoo! Answers Visit the source

Was this solution helpful to you?

Related Q & A:

Just Added Q & A:

Find solution

For every problem there is a solution! Proved by Solucija.

  • Got an issue and looking for advice?

  • Ask Solucija to search every corner of the Web for help.

  • Get workable solutions and helpful tips in a moment.

Just ask Solucija about an issue you face and immediately get a list of ready solutions, answers and tips from other Internet users. We always provide the most suitable and complete answer to your question at the top, along with a few good alternatives below.