Solve the logarithmic equation log(3x)=log(5)+log(x-4). Reject any value that is not in the domain of the?
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Solve the logarithmic equation log(3x)=log(5)+log(x-4). Reject any value that is not in the domain of the original logarithmic expressions.
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Answer:
log(3x) = log(5) + log(x - 4) log(3x/5) = log(x - 4) 3x/5 = x - 4 3x = 5x - 20 2x = 20 x = 10
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Other answers
log (3x) = log 5 + log (x - 4) log (3x) = log [5(x - 4)] and if log M = log N, then M = N 3x = 5(x - 4) 3x = 5x - 20 20 = 2x x = 10 10 is a valid solution, so x = 10 check: log 30 = log 5 + log 6 ? log 30 = log 30 checks x = 10
log(3x) = log(5) + log(x-4) log (3x) = log[5(x - 4)] 3x = 5(x - 4) 3x = 5x - 20 2x = 20 x = 10
log(3x)=log(5)+log(x-4). log(3x) = log(5x-20) 3x = 5x -20 2x = 20 x = 10
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