Apothem of a regular hexagon with a side length of 3?

Find the area of a hexagon whose side length is 16in and the apothem is 8^3?

  • A) 64^3 in2 B) 384^3 in2 C) 256^3 in2 D) 128^3 in2 Can somebody explain this problem? Thanks!

  • Answer:

    The side length, s, and apothem, a, are linked by the formula a = s*sqrt(3)/2 so if s = 16, a = 16*sqrt(3)/2 = 8sqrt(3) I presume you mean 8sqrt(3) not 8^3. The area of a hexagon is given by A = (3*s^2/2)*sqrt(3) if s = 16, A = (3*16^2/2)sqrt(3) = 384sqrt(3) in2 (answer b)

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Assuming that ^ means square root, it's B.

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