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What is the difference between an Amplifier and a Speaker?

Imagine you are in an open field where two loudspeakers are set up and connected to the same amplifier so that?

  • Imagine you are in an open field where two loudspeakers are set up and connected to the same amplifier so that they emit sound waves in phase at 688 Hz. Take the speed of sound in air to be 344 m/s. 1. What is the shortest distance "d" you need to walk forward to be at a point where you cannot hear the speakers? Express your answers in meters to three significant figures. This is what I have so far... Since, 𝜆=344m/s/688Hz=0.500m, the shortest distance that will create destruuctive interference is 0.5𝜆=(1/4)m (since both speakers are in phase - remember the condition for destructive interference is (m+1/2)𝜆 for when two sources are in phase) as the person walks forward, the distance from each speaker becomes the hypothenuse of a right triangle, So, distance from a=√(3^2+d^2 ) distance from b=√(3.5^2+d^2 ) difference in both distances must equal 1/4 √(3.5^2+d^2 )-√(3^2+d^2 )=0.25m I know that my set up is right but I can't figure out where to go from here...PLEASE HELP!

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    I'm having trouble figuring out the geometry. Are the speakers 6.5m apart? Was this given? If not where does the 3 and 3.5 come from in your equations? Also was the starting point 3m from one speaker and 3.5m from the other also given? If not, why did you choose it?

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The shortest distance is somewhere on the line joining the two loudspeakers. This is (3 + 3.5) metres distance between the two speakers. Okay, this is a standing wave question and not what you think -- there are no triangles and hypotenuse to worry about. Unless there is more data you didn't tell us. [Is the distance between the speakers given? If less than 6.5 m we cannot solve it. We are in the middle of a fringe pattern. You seem quite capable of working out mathematically so I won't do it for you. Just get the wavelength. You've got frequency and velocity so it should be easy. You already got that as 0.5 m. Now you are 3.5m from one source and 3.0m from the other. Is this in phase or out of phase? (One wavelenth difference). Let d be the distance moved to where you hear no sound. If you know standing waves, the nodes and antinodes are umm, how many wavelengths apart? If you cannot see this, then use d in the equation, and lessen 3.5m by d, and increase 3.0m by d, and then find the path difference, and equate it to half-wavelength. Do you know why? That should give d. As to whether you have moved in a straight line between the two loudspeakers or gone sideways to a different spot out of this line, we need more info or a diagram at the beginning to tell us. A last question for you: why are the two loudspeakers in an open space?

Minerva

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