Glass thickness?

What is the steady state rate of heat flow through a pane of glass that is 40.0 cm by 30.0 cm with a thickness?

• What is the steady state rate of heat flow through a pane of glass that is 40.0 cm by 30.0 cm with a thickness of 4.00 mm when the outside temperature of the glass is -10.0°C and its inside temperature is 25.0°C? The thermal conductivity of glass is 0.105 W/(m∙K), the specific heat of glass is 0.180 cal/(g∙°C), and 1 cal = 4.190 J. Help me please! Thanks

• Answer:

  Rate of heat transfer = k*A(T1 - T2) / d where k = thermal conductivity (W/(m*K) d = thickness (m) T1 and T2 = inside - and outside temperatures A = window area (m^2) Rate = 0.105*(0.4*0.3)(25 - -10) / 0.004 Rate = 110.25 Watt OG