How to find the equation of a tangent to the curve at P?
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A curve has equation y=4/(3x-4) and P(2,2) is a point on the curve. Find the equation of the tangent to the curve at P. We got the solution which is: dy/dx = -4(3x-4)^-2 *3 if x=2, m=-3 Eqn of tangent: y-2=-3(x-2) Can someone explain to us how they did the solution and the answer above? I know it's kinda stupid but I really need help. Also, how did they able to place the (3x-4) in the numerator? I really didn't get why there is a ^-2. Please explain! Thanks :D
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Answer:
triky
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