Is general gas law similar with combined gas law?

Consider 4.30 L of a gas at 365 mmHg and 20 C. Combined Gas Law. I set it up but dont know how to calculate?

• Consider 4.30 L of a gas at 365 mmHg and 20 C. If the container is compressed to 2.90 L and the temperature is increased to 32 C what is the new pressure (P2) inside the container? Assume no change in the amount of gas inside the cylinder. (365)(4.30)/293K = ?(2.90)/313

• Answer:

  algebra... you need to rearrange to solve for the unknown. It's easier if you rearrange the symbolsbefore replacing them with numbers you want to solve for P2, so you want P2 by itself P1V1 / T1 = P2V2 / T2 to get T2 on the other side multiply both sides by T2 P1V1T2 / T1 = P2V2 to get V2 on the other side divide both sides by V2 P1V2T2 / (V2T1) = P2 now plug your numbers in P2 = 365 mmHg x 4.30 L x 313 K / (2.90 L x 293 K) = 578 mmHg