Find an equation of the plane through the point and perpendicular to the given line?

Find the equation of the line passing through the point (1/2, -2) that is perpendicular to the line given by?

  • Find the equation of the line passing through the point (1/2, -2) that is perpendicular to the line given by 3x-2y = 5

  • Answer:

    3x - 2y = 5 -2y = -3x + 5 y = (3/2)x - 5/2 slope of the given line is 3/2 slope of a line perpendicular is -2/3 y = mx + b -2 = (-2/3)(1/2) + b -2 = -1/3 + b -2 + 1/3 = b -5/3 = b y = (-2/3)x - 5/3 or y - y1 = m(x - x1) y - (-2) = (-2/3)(x - 1/2) y + 2 = (-2/3)x + 1/3 y = (-2/3)x - 5/3

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