(10 points please help!) Calculate the free energy of the reaction?
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2NO2(g) <----> N2O4(g) ; deltaH= -56.8 kJ deltaS= -175 J/K In a container at 298 K, N2O4 and NO2 are mixed with initial partial pressures of 2.4 atm and 0.42 atm respectively. Calculate the free energy of the reaction.
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Answer:
It is possible relate the standard Gibbs free energy ∆Gº (at 25C, 1 atm pressure) and the Gibbs free energy ∆G, at any temperature and pressure through the following equation: ∆G = ∆Gº + RTln(Q) The following site will explain the terms and lead you through a similar problem. http://www.cartage.org.lb/en/themes/sciences/chemistry/miscellenous/helpfile/spontaneityentropy/TheGibbsfree.htm You'll still have to calculate the standard-state free Gibbs energy of reaction, required in the equation above, using this formula: ∆Gº = ∆Hº - T ∆Sº The site below may also be of help. http://chemed.chem.purdue.edu/genchem/topicreview/bp/ch21/gibbs.php It's basically a lot of number crunching. Hope this info helps.
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