10 points! solve the equation show work log (x)=log (7)?
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4^x=4^2x+1 2^4x+1=2^2x-3 log (x)=log (7) log(x+20)=log(9x-20)
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Answer:
For the third equation: x=7. All u do is get rid of the log. For the fourth equation: drop the log. x+20=9x-20 40=8x 5=x
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Other answers
1. 4^x = 4^(2x+1), SO, x = 2x+1, ===> 2x-x = -1, OR, x = -1 >==================================< ANSWER 2. 2^(4x+1) = 2^(2x-3) Hence, 4x+1 = 2x-3, ===> 4x -2x = -3 -1, 2x = -4, x = -2 >==================================< ANSWER 3. log (x) = log (7), By definition, x = 7 >==================================< ANSWER 4. log(x+20) = log(9x-20), Hence, x+20 = 9x -20, 9x -x = +20 +20, 8x = 40, x = 40/8 = 5 >==================================< ANSWER
Fazaldin A
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