What is the 1st derivative of: F(x) =int[(t^2+1)^(1/2)]dt from 'sqrt(x) to 'x' ?
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what is the 1st derivative of: F(x) =int[(t^2+1)^(1/2)]dt from 'sqrt(x) to 'x' ???
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Answer:
use one of Leibnitz's theorems.......√( x² + 1 ) - √ ( x + 1) [ 1 / ( 2√x ) ]..theorem results are if F(x) = int over t in [ a(x) , b(x) ] of { g(t)dt } then dF / dx = g(b(x)) [ db /dx ] - g(a(x)) [ da / dx ]
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