What is the molarity of a nitric acid solution if 43.55 mL 0.1000 M KOH solution is needed to neutralize 30.00?
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mL of unknown solution? Answer in M!
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Answer:
HNO3 + KOH → H2O + KNO3 Supposing the missing units to be "30.00 mL": (43.55 mL) x (0.1000 M KOH) x (1/1) / (30.00 mL) = 0.1452 M HNO3
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