Help me for Physics, please?

Physics help 10 points best answer help please?

• Physics help 10 points best answer help please? Physics help 10 points best answer help please? 1.) Caslculate the period of a pendulum on Earth with a length of 2.50 meters. 2.) Calculate the length of a pendulum with a period on Earth of 3.00 seconds. 3.) Calculate the acceleration due to gravity on a mystery planet where a 0.25 meter long pendulum has a period of 3.00 seconds. 5.) If a pendulum has a period of 3.00seconds. What is its frequency? 4.) If a pendulum clock were running fast in your home, what could you do to fix it so that it would keep better time? 6.) You notice it takes 10 seconds for 2 water waves to reach the beach. What is the frequency of these waves? What is the period? 7.) A water has a wavelength of 3 meters and a frequency of 0.20 Hz. What is the speed? 8.) A sound waves has a speed of 340 m/s and a frequency of 800 Hz. What is its wavelength? thanks no rude comments please you don't have to help!! and thanksd to those who helped me!!! PLease show work!!! thanks :D <3

• Answer:

  The Formula that I would use to answer question (1-3) is: T=(2π√L)/√g, where, T = time period L = effective length g = acceleration due to gravity Solution 1: Here, L = 2.50 m T = ? So, T = 2 x 3.1416 x √(2.50/9.8) Or, T = 3.17 sec (Ans.) Solution 2: Here, L = ? T = 3 sec So, L=T^2 g/4π^2 Or, L = (3^2 x 9.8) / {4 x (3.1416)^2} Or, L = 2.23 m (Ans.) Solution 3: Here, L = 0.25 m T = 3 sec g = ? So, g = (4 π^2 L) / T^2 Or, g = {4 x (3.1416)^2 x 0.25} / 3^2 Or, g = 1.097 ms^-2 (Ans.) Solution 4: A pendulum clock can only move fast if there is a variation of acceleration due to gravity (assuming effective length to be constant). So, by keeping it at a perfect height (from the center of earth), this problem could be solved. [I'm not sure about this answer. Please Check this one.] Solution 5: Here, T = 3 sec Frequency, f = ? The formula is, T = 1/f Or, f = 1/T Or, f = 1/3 Or, f = 0.33 Hz (Ans.) Solution 6: Here, Number of water waves, N = 2 Time, t = 10 sec f = ? T = ? The formula is, f = N/t Or, f = 2/10 Or, f = 0.2 Hz (Ans.) Now, T = 1/f Or, T = 1/0.2 Or, T = 5 sec (Ans.) Solution 7: Here, Wave length, λ = 3 m f = 0.20 Hz The formula is, Speed, v = fλ Or, v = 3 x 0.20 Or, v = 0.6 m/s (Ans.) Solution 8: Here, speed, v = 340 m/s f = 800 Hz wavelength, λ = ? So, v = fλ Or, λ = v/f Or, λ = 340/800 Or, λ = 0.425 m (Ans.) Hope this answers the question.