The base of an isosceles triangle is 14 in. long and the equal sides are each 25 in. long. Find the height h o?

h^2 = 25^2-7^2 = 32*18 h = 24 in

You would use the Pythagorean Theorem for this problem to solve for the height, because the height from the base to the opposite vertex is perpendicular to the vertex, and divides the triangle into to equal halves. Pythagorean Theorem: a^2 + b^2 = c^2 where c is the length of the hypotenuse, and a and b are the two legs connected to form the right angle. So you would basically plug in what you know and solve for the height, which is one of the legs of the triangle. Dividing the base in 2 will give you one of the legs (14 in / 2 = 7 ) and one of the equal sides of the triangle (25 in.) would give you the hypotenuse. Solve: 7^2 + b^2 = 25^2 49 + b^2 = 625 b^2 = 625 - 49 b^2 = 576 √b^2 = √576 b = 24 So the height would be 24 inches.