How do I randomly select a string from an array in swift?

The static method atLongLast takes an array a of non-empty Strings and returns a String containing just the la?

• The static method atLongLast takes an array a of non-empty Strings and returns a String containing just the last character of the longest String in a. (If there are more than one equally longest Strings in a, use the one with the smallest index in a. If a has no elements, return the empty String "".) For example: atLongLast( { "quite", "a", "short", "array" } ) has the value "e", and atLongLast( { "has", "one", "humongously", "long", "string" } ) has the value "y". Which of the following are suitable definitions for atLongLast? public static String atLongLast( String[] a ) { if ( a.length == 0 ) return ""; int maxIdx = 0; for ( int i = 1 ; i < a.length ; i++ ) { if ( a[ maxIdx ].length() < a[ i ].length() ) maxIdx = i; } return a[ maxIdx ].substring( a[ maxIdx ].length() - 1 ); } public static String atLongLast( String[] a ) { String s = ""; for ( int i = 0 ; i < a.length ; i++ ) { if ( s.length() < a[ i ].length() ) s = a[ i ]; } if ( s.equals( "" ) ) return ""; else return s.substring( s.length() - 1 ); } public static String atLongLast( String[] a ) { String s = ""; int maxIdx = 0; for ( int i = 1 ; i < a.length ; i++ ) { if ( a[ maxIdx ].length() < a[ i ].length() ) { s = a[ i ].substring( a[ i ].length() - 1 ); maxIdx = i; } } return s; } A I only B II only C I and II only D I and III only E I, II, and III I put D and I got it wrong, can someone please explain this to me and what the right answer is? Thank you!!

• Answer:

  sry cant get u