Using a For loop you must find the average of all the even numbers and all the odd integers between 0 and 100?

something like this (this is a java example but you'll get the jist of it). A for lus that goes from 0 to 100, and every count it'll check if the teller is even or not (% is modulus sign, to get the rest value of a devide (2 / 2 = 0 for example). It'll increase the tellers by one and increase the sum with the value of i, then devide the sum by count and you have your avarage. double oddSum = 0, evenSum = 0, oddCount = 0, evenCount = 0; for(int i; i < 101; i++){ if(i % 2 == 0){ evenSum += i; evenCount++; } else{ oddSum += i; oddCount ++; } double avgEven = evenSum / evenCount; double avgOdd = oddSum / oddCount; }

// number of odds int nbOdd = 0; // number of evens int nbEven = 0; // running total of odds int totalOdd = 0; // running total of evens int totalEven = 0; // start loop for(i=1;i<101;i++) { // test using modulus if (i % 2 == 0) { // even nbEven++; totalEven = totalEven + i; }else { // odd nbOdd++; totalOdd = totalOdd + i; } } // end loop // compute averages double avgOdd = totalOdd / nbOdd; double avgEven = totalEven / nbEven;

k=1; l=1; a=0; b=0; for(i=0;i<=100;i++) { if(i%2==0) { a=a+i; even_av=a/k k++; } else { b=b+i; odd_av=b/l l++; } }