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What would be a good skateboard combination?

A 2.20 kg skateboard is coasting along the pavement at a speed of 4.0 m/s.?

  • When a 0.850 kg cat drops from a tree vertically downward onto the skateboard. What is the speed of the skateboard-cat combination.

  • Answer:

    This is conservation of momentum. Initial momentum: (2.20 kg)*(4.0 m/s) = 8.8 kgm/s Initial momentum = Final momentum Final momentum: (2.20 + 0.850 kg)*v = 8.8 kgm/s Solve for velocity. v = 2.885 m/s

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initial KE + initial PE= 1/2 MV^2 + mgh =final KE + final PE= 1/2 MV^2 + mgh since initial PE and final PE are zero for this problem, the equation would look like this: initial KE which is 1/2 MV^2 = final KE which is 1/2 MV^2 .5 (2.2)(16) = 17.6 17.6 = .5 (2.2 +.850)(v)^2 final velocity would be 3.39

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