What is the derivative of the function.?
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What is the derivative of the function. f(x) = ln (x+9/x-9)
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Answer:
y = ln[(x+9)/(x-9)] => simplify first: y = ln(x + 9) - ln(x - 9) dy/dx = dy/dx[ln(x + 9) - dy/dx[ln(x - 9)] => use the chain rule: y' = dy/dx(x + 9)/(x + 9) - dy/dx(x - 9)/(x - 9) y' = 1/(x + 9) - 1/(x - 9) y' = (x - 9 - x - 9)/((x + 9)(x - 9)) y' = -18/(x^2 - 81)
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Other answers
derivative of logx is 1/x so its derivative will be...... 1/(x+9/x-9)*derivative of the term (x+9/x-9) .....which u can find by u/v rule...
spidy7
-(18/(-81 + x^2))
JOS J
derivative of ln x = 1/x so use chain rule and quotient rule.
Deezy22
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