What is the approximate length of the diagonal of a square with side length of 20 centimeters ?
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what is the approximate length of the diagonal of a square with side length of 20 centimeters ? A - 14.1 cm B - 20.0 cm C - 25.0 cm D - 28.3 cm please explain :D
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Answer:
a^2 + b^2 = c^2 a and b are the sides of the square, so are both 20, c is the diagonal 20^2 + 20^2 = c^2 400 + 400 = c^2 800 = c^2 take the square root of both sides c = 28.28 or 28.3 cm
Tammie at Yahoo! Answers Visit the source
Other answers
draw it and write 20 cm on top of each side of the square. draw the two diagonals. now you should see that you get two right triangles. each triangle has 2 sides of 20 cm, and the hypothenuse is the diagonal. using h^2= a^2+b^2, where a and b are 20 in this case, we get h^2= 20^2 + 20^2= 800 h= sqrt(800)= 28.3
james brown
D. All sides are equal in a square. Split the square into two. Use Pythagorean Theorem. Let c be the length of the diagonal. (20^2*20^2)^1/2= 28.3
LuLu
exactly would be 20 * sqrt(2) ... so 20 x 1.4 = 28 --- so D {no need to use 1.4142..}
SumDude
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