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Describe how you would prepare the following aqueous solutions?

How to prepare 100 ml solution of .2M with anhydrous solids?

  • Prepare 100mL each of .2M sodium carbonate and .2M sodium hydrogen carbonate solutions from anhydrous solids; later, use each of these to prepare 100 ml of the corresponding .02M solution. Describe the process of making each of these solutions. I have no idea how to do this, please help!

  • Answer:

    OK--the molecular weight of sodium carbonate is 105.9884 g/mol. Multiply this value by 0.2 to get grams/L; since you're only making up 100 mL, multiply *that* value by 0.1. Same thing for sodium hydrogen carbonate, which has a mw of 83.98 g/mol. To make a 0.02 M solution, you just take these two solutions and dilute by 1/10.

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