What course should the second ship take and what distance will the second ship travel? (information inside)?
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A ship leaves a port and sails 30 miles due East. Then the ship turns and sails 40 miles in the direction N 30 degrees East, and drops anchor. A second ship leaves the same port to rendezvous with the first ship. What course should the second ship take? What distance will the second ship travel?
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Answer:
x = 30 + 40cos60 = 50 y = 40sin60 = 34.64 d² = 50² + 34.64² =3700 d = 60.83 miles= distance ==> answer tanA = 50/34.64 = A = 55.3 course = N55.3°E ==> answer
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