How to find the equation and the set of values for the curve? PLEASE HELP, 10 POINTS?
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A curve is such that dy/dx = 3 / (1+2x)^2 and the point (1, 1/2) lies on the curve. Find the equation of the curve. Then find the set of values of x for which the gradient of the curve is less than 1/3. Please help, 10 points?
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Answer:
Where x = 1... dy/dx = 3/3² = 1/3 Now.. y - ½ = 1/3 * (x - 1) Good luck!
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