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What is a band level?

A rock band plays at a 68 dB sound level. How many times greater is the intensity from another rock band play?

  • A rock band plays at a 68 dB sound level. How many times greater is the intensity from another rock band playing at 113 dB?

  • Answer:

    As usual, the distance to the sound source is missing. Doubling the distance means 6 db decrease of sound level. A rock band will never play at a 68 dB maximum sound level. The difference between 113 dB and 68 dB is 113 - 68 = 45 dB. That is a factor of 10^(45/10) = 31622.78 The other rockband is 316223 times louder. If this help. Cheers ebs PS: A decibel value without telling the measured distance is really useless. A jackkhamme has not 110 dB and a rock band has not 113 dB. The closer you go to the noise source the more decibels you will measure.

angelyza... at Yahoo! Answers Visit the source

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An ordinary conversation is approximately 60dB... and since decibels are on a logarithmic scale, each gain of 10 is twice as loud. So, using 60dB as the benchmark, a reading of 70dB is twice as loud; 80 dB is four times as loud; 90 is 8 times as loud; 100 is 16 times as loud; and 110 is 32 times as loud. As you can see, it's quite a difference.

Bob

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