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Assume that the number of viruses present in a sample is modeled by the exponential function "f(t) = 10t," whe?

  • Assume that the number of viruses present in a sample is modeled by the exponential function "f(t) = 10t," where t is the elapsed time in minutes. How would you apply logarithms to determine when the sample will grow to 5 billion viruses?

  • Answer:

    By 10t do you mean 10 to the t power? Then write the equation 5 000 000 000 = 10 ^ t and log both sides log 5 000 000 000 = t log 10 and log 10 = 1 so t = log 5 000 000 000 minutes; do that on your calculator

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Use a caret ^ or the shift 6 to raise to a power f(t) = 10^t ............it has to be to a power to be an exponential function 5 X 10^9= 10^t.......take the log of each side log(5 X 10^9) = log 10^t..........log property is log N^p = p*log N log(5 X 10^9) = tlog 10............log(b) b = 1 and log = log(10) t= log(5 X 10^9) t= 9.698970004336017 t = 9.7 minutes

Sue

 f(t) = 10t ... is NOT an exponential function    ... use " ^ " to denote exponents:    ... Example: A = (Ao) • e^(k  •  t)

Geronimo

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