Identify the acid and base on left side of the equation and the conjugate acid and conjugate base on right?
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HCOOH(aq) + H2O(i) <----------> HCOO-(aq) + H3O+(aq) NH3(aq) + H2S(aq) <-----> NH4+(aq) + HS-(aq)
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Answer:
1st Equation: HCOOH: Acid H2O: Base HCOO-: Conjugated Base H3O+: Conjugated Acid 2nd Equation: NH3: Base H2S: Acid NH4+: Conjugated Acid HS-: Conjugated Base In general, the acid is the one that loses a proton (H+), converting into a conjugated base. And the one that accepts the proton is the base, converting into a conjugated acid. That's it, greetings.
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