A density value is reported as 10.67g/ml.the correct or accepted value is 7.43g/ml.calculate the percent error

I think you mean the true value, or value you should of gotten is 7.43 and you got 10.67. Or is it the other way around? I'll do it using these two values The equation would be: ( |true value- experimental value| / |True Value| ) X 100% = percent error True value= the value that you should have gotten Experimental Value= the value that was discovered through the experiment (incorrect value) 1) |7.43- 10.76| = 3.33 g/mL (the | mean absolute value, making a negative answer always positive) 2) 3.33/7.43= .448 (no units, they would cancel out.) 3).448 x 100%= 44.8% error