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How many grams of sodium carbonate are present after the reaction is complete?

Calculating grams of Na in 16 g of Na2Co3 (sodium carbonate)?

  • How do you calculate the number of grams in Na that are in 16.0 grams of Na2Co3 (sodium carbonate)? Thanks

  • Answer:

    Step 1: Find the molar mass of Na2CO3 and Na. Na2CO3 = 2(22.99) + 12.01 + 3(16) = 105.99g Na = 22.99g Step 2: Find the mole ratio between Na2CO3 and Na: There are 2 moles of Na to 1 mole of Na2CO3, so the mole ratio is 2 to 1 or 2:1. Step 3: Find the # of grams of Na in Na2CO3. 16g Na2CO3 ( 1 mol Na2CO3 / 105.99g Na2CO3) (2 mol Na / 1 mol Na2CO3) (22.99g Na / 1 mol Na) = 6.94g Na Bill

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I do not have a calculator or periodic table with me right now. But I can show you the setups. 1) First using the periodic table, calculate the molar mass(molecular weight) of Na2CO3. 2) Start with the given grams of Na2CO3, convert to moles of Na2CO3 16 g Na2CO3 (1 mole Na2CO3/molar mass of Na2CO3) 3) The formula shows that 1 mole of Na2CO3 contains 2 moles of Na. 16 g Na2CO3 (1 mole Na2CO3/molar mass of Na2CO3)(2 mole Na/1 mole Na2CO3) 4) Convert the moles Na into grams sodium, which will be the final set up. 16 g Na2CO3 (1 mole Na2CO3/molar mass of Na2CO3)(2 mole Na/1 mole Na2CO3)(22.99 g Na/1mole Na) Use the step. 4 to find the answer for your problem. Your answer must have 2 significant digits.

Pushpa Padmanabhan

just look at ur periodic table. and then add up the grams u see for ur atomic mass. u have 2 na and 3 co. then firgure out the precentage of one Na out of the whole compound. after get what that precentage is out of all the grams in the entire compound

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