Calculate the concentration of OH^- ions in sodium hydroxide solution of concentration 0.1mol L^-1?
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Show working please, I'm really lost
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Answer:
0.1 moles per litre. Sodium hydroxide has a chemical formula of NaOH. So you can represent it, in terms of concentration, like this: [Na+] [OH-] The 0.1 moles per litre refers to having 0.1 mol of Na+ and 0.1 mol of OH- in there to make a combined total of 0.1 mol L-1 NaOH. If it was something like Al(NO3)3, and you were asked for the concentration of NO3 in a 0.1 mol per litre solution, then it would be 0.3 mol because there are three times as many NO3s as there are Al atoms.
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Other answers
NaOH --> Na(+) + OH(-) So 1 mole of NaOH contains 1 mole of Na(+) ion and 1 mole of OH(-) ion. 0.1 mol / L NaOH means that in 1 litre, there is 0.1 mole of NaOH. So in 0.1 mol / L of NaOH, it has 0.1 mole of OH(-) ions.
αSCieNCeΩ
NaOH= Na+ + OH- 0.1 mol/L = [OH]- therefore, the ion concentratiom of OH ions is 0.1 mol/L
PalDsilva♥
What calculate? NaOH ionizes 100% 0.1 mol NaOH ionizes to 0.1mol Na+ and 0.1mol OH- [OH-] = 0.1M
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