What is the total heat capacity of the calorimeter?

What is the heat capacity of the calorimeter?

• A coffee cup calorimeter contains 23.77 g of water, at 20.9 def C. then 47.66g of water, with an initial temperature of 66.6 deg C, was added to the calorimeter. The final temperature of the water in the calorimeter was 24.4 deg C. What is the heat capacity of the calorimeter? The specific heat of water is 4.184 J g^-1 C^-1 PLEASE PLEASE HELP!!!!!:( please provide the steps/work on how to do this problem too please.

• Answer:

  let the heat capacity be C J K^-1 Heat energy given by hot water=46.66*4.184*(66.6-24.4)=8238.513 J Heat energy taken by cold water=23.77*4.184*(24.4-20.9)=348.087 J Heat energy taken by vessel=C*(24.4-20.9)=3.5C J If there is no heat energy loss then, Heat energy given by hot water=Heat energy taken by cold water and vessel =>8238.513=348.087+3.5C =>C=2254.407 Thus heat capacity of the calorimeter is 2254.407 J K^-1 or 2254.407 J C^-1.