A test charge q0=1.6x10^-16C is placed at point P in a space experiences a force with a magnitude of?
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7.2x10^-12N due to the electric field. The magnitude of the electric field at point P is_____.
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Answer:
electric field at a point can be explained in two ways...intensity which is a vector having direction same as force,potential which is a scalar.electric field intensity is defined as force experienced by test charge when it kept in a field. so,E=F/q E=7.2*10^4/1.6=4.5*10^4 n/c.
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