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How to find the total momentum before and after a collision?

Physics Angular Momentum Problem?

  • A projectile of mass m moves to the right with a speed vi. The projectile strikes and sticks to the end of a stationary rod of mass M, length d, pivoted about a frictionless axle perpendicular to the page through O. We wish to find the fractional change of kinetic energy in the system due to the collision. (Use any variable or symbol stated above as necessary.) image: http://www.webassign.net/serpse8/11-p-051.gif (b) What is the magnitude of the angular momentum of the system before the collision about an axis through O? Ltotal = (c) What is the moment of inertia of the system about an axis through O after the projectile sticks to the rod? Itotal = (d) If the angular speed of the system after the collision is ω, what is the magnitude of the angular momentum of the system after the collision? Ltotal = (e) Find the angular speed ω after the collision in terms of the given quantities. ω = (f) What is the kinetic energy of the system before the collision? K = (g) What is the kinetic energy of the system after the collision? Ktotal = (h) Determine the fractional change of kinetic energy due to the collision. |ΔK| =

  • Answer:

    Not a very difficult problem but web assign has a terrible way of entering answers... Anyway if you have the serway book the answer is in the back. Page A-32 chapter 11 problem 51

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Just finished this, so I suppose. Madison by chance? B. L = r x p. Notice the radius from the axis of rotation end of the rod is d/2. the initial momentum is the mass of the ball times the initial velocity. L = mv(d/2). v initial that is C. I of a rod is (1/12)ML^2. I of a ball is mr^2. L = d and r = d/2, so you can substitute those in. The moments of inertia can be added so Itotal = (1/12)Md^2 + m(d/2)^2 D. L = Iw. I was determined in C so just multiply by omega. E. Use your answers from b and d to solve for omega. F. KE = (1/2)mv^2 G. KEfinal = (1/2)Iw^2. Using your total moment of inertia and omega from C and E and some simplifying you will get (3(m^2)(v^2))/(2(M+3m)) H. (KEinitial - KEfinal)/KEinitial

nick

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