Solve the following set of equation by elimination method?
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Solve the following set of equation by elimination method 3x-4y-z=1 x+2y-3z= -2 4x+3y-2z= -1 and solve by substution 4x-y-z = 4 2x+5y+3z = -3 3x+2y-4z = -2
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Answer:
This is the last one I'll do before going to bed. Equation numbers in parentheses. 3x - 4y - z = 1 (1) x + 2y - 3z = -2 (2) 4x + 3y - 2z = -1 (3) 6x - 8y - 2z = 2 (1) -2x + 11y = -3 (3 - 1 ==> 4) 2x + 4y - 6z = -4 (2) 12x + 9y - 6z = -3 (3) 10x + 5y = 1 (3 - 2 ==> 5) -10x + 55y = -15 (4) 60y = -14 (5 + 4 ==> 6) y = - 7/30 (6) Answer 10x - 35/30 = 1 (6 ==> 5) x = 65/300 = 13/60 (5) Answer 39/60 + 28/30 - z = 1 (5, 6 ==> 1) z = (39 + 56 - 60)/60 = 35/60 = 7/12 (1) Answer The solution is x = 13/60, y = -7/30, z = 7/12 4x - y - z = 4 (1) 2x + 5y + 3z = -3 (2) 3x + 2y - 4z = -2 (3) z = 4x - y - 4 (1) 2x + 5y + 12x -3y -12 = -3 (1, 2 ==> 4) 14x +2y = 9 (4) 3x + 2y -16x + 4y + 16 = -2 (1, 3 ==> 5) -13x + 6y = -18 (5) 2y = 9 - 14x (4) 6y = 27 - 42x (4) -13x + 27 - 42x = -18 (4, 5 ==> 6) 45 = 55x (6) x = 9/11 (6) Answer 2y = 9 - 126/11 = - 27/11 (6 ==> 4) y = - 27/22 (4) Answer z = 36/11 + 27/22 - 4 (6, 4 ==> 1) z = (72 + 27 - 88)/22 = 1/2 (1) Answer The solution is x = 9/11, y = -27/22, z = 1/2
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Other answers
wow there was a time I knew how to do this. Frustrating.
Payne
-3(3x-4y-z=1) x+2y-3z=-2 ....................... -8x + 14 y = -5 -2(3x-4y-z=1) 4x+3y-2z= -1 ..................... -2x + 11y = -3 2(8x + 14y = -5) 8(-2x + 11y = -3) ............................ 116y = -34 y = -34/116 x = -13/116 z = ? Damn I don't think I did that right lol.
Schlonger34
to start you off: the second equation (set 1) looks like the easiest to work with,,,,M(-3) and add to the first equation (this eliminates the 3x) then M(-4) and add to the last equation (again eliminates the x term). Then move to the next variable (y) and do similar operations to clear out the y terms....then do same with z ...good luck ! By substitution? Second set of equations: solve the first equation for either y or z . if y then you get y = 4x-y-4 substitute this into the last equation (or the second equation) and continue...solve next for one of the other variables (other than the one you used first)...this substitution process can be tricky so be careful and include steps slowly. Good luck ! You are solving by different methods so you will see that in certain cases one method will work quicker than another. Be sure to check your final answer in the orginial equations.
travlin
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