Find an equation of the plane through the point and perpendicular to the given line?

Math Question(s): Write and equation of the line containing the given point and perpendicular to the give line?

• (0,9);3x+5y=8 The equation of the line is y=? (2)Find an equation of the line containing the given pair of points (-5,0) and (0,9) What is the equation of the line? y=? (3)Find an equation of the line containing the given pair of points (2,5) and (6,6) y=? (4) Graph the line with the given point and slope The line through (1,-1) with slope 5/4 phew!

• Answer:

  slope of 3x + 5y = 8 is -3/5, slope of perpendicular is 5/3, so equation is 5x – 3y = c, and to get c, plug in (0,9) making it 5x – 3y = -27 slope is 9/5 and 9 is the y intercept, so y = 9x/5 + 9 slope is 1/4, so x – 4y = c ∙ ∙ ∙ 2 – 4(5) = -18 ∙ ∙ ∙ x – 4y = -18 plot (1,-1). from there go up 5, right 4 to (5,4), plot that, and draw a line through them.