Determine if you can exclude any value from the domain [x^2 - 6x] / [x^2 + 16]?
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Answer:
You don't specify in what field. In the Complex field, the values 4i and -4i (4i)^2 = -16 (-4i)^2 = -16 would lead to singularities. [(4i)^2 - 6(4i)] / [(4i)^2 + 16] = (-16 - 24i) / (-16 + 16) = -4(4 + 6i) / 0 (4 + 6i) is not equal to zero therefore this is not a case of 0/0 (which can sometimes be resolved) In the real fields (e.g., field of rational numbers), there are no numbers to be excluded.
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