Is the axiom of choice really related to choice?
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If we specifically do not assume the Axiom of Choice, are all the sets that we can prove to exist specified by some finite formula? (All the other Zermelo-Frankel set theory axioms seem constructive to me, so I want to say yes, but I'm not sure.) If not, what's an example of such a set? A slightly related questions: in a previous question I had about the Axiom of Choice, some of the answerers mentioned the distinction between a function and "a function you can name". Assuming the Axiom...
Answer:
I believe that your first mistake is that the ZF theory is a lot less constructive then it seems. The...
grautur at Mathematics Mark as irrelevant Undo
Other solutions
See Scott Aaronson's answer to How can the BanachâTarski paradox make sense to mathematical laymen? There he mentions that denial of the axiom of choice also leads to bizarre results. Could there be a weakened version of the axiom of choice...
Answer:
Sure. For example: Axiom of countable choice Axiom of dependent choice In fact there's a whole jungle...
Alon Amit at Quora Mark as irrelevant Undo
I'm curious specifically about processes whose outcomes cannot be computed by other means. It is my understanding that axioms should be assumed as true because they are self-evidently true, and this is what distinguishes useful mathematics from that...
Answer:
As you noted in the question, there is certainly utility to using AC in applied mathematics. However...
Mark Ettinger at Quora Mark as irrelevant Undo
I get the idea of set theory however I do not understand the axiom of choice nor why it is significant.
Answer:
The axiom of choice says that the Cartesian product of nonempty sets is nonempty. That is (for example...
TheMathe... at Yahoo! Answers Mark as irrelevant Undo
Here's the proof: First, we note that there's a one-to-one function from SSS to 2S2S2^S given by xâ¦{x}xâ¦{x}x \mapsto \{x\}. Now we assume that there's a bijection ÏÏ\phi between SSS and 2S2S2^S. Then there is some xâ...
Answer:
No, this proof does not require the Axiom of Choice (AC). But it's very difficult to work with cardinalities...
Joe Blitzstein at Quora Mark as irrelevant Undo
Can it be discarded without changing anything we understand about the physical world? Would the mathematical expression of any current physical theory be unsound? Would differentiation or integration suddenly have no theoretical basis, for example...
Answer:
It is not. The physical laws are always formulated as an algorithmic computation for producing an answer...
Ron Maimon at Quora Mark as irrelevant Undo
In other words, what interesting statements require the existence of choice functions for uncountably infinite collections of sets?
Answer:
As far as I know, countable choice is not strong enough to prove the ultrafilter lemma (Boolean prime...
Qiaochu Yuan at Quora Mark as irrelevant Undo
Consider an organization of your choice and carefully go through marketing research process to solve marketing related problems or opportunity that may be relevant to chosen ...show more
NKWRCBLSHCL7UMSWPAFMIM72IQ at Yahoo! Answers Mark as irrelevant Undo
Multiple choice: The objective with pain is to: (A) Identify the location of the primary pain (B) Identify the secondary locationsof pain (C) A & B (D) None of the above Note: I found a sentence in my text that reads, "The ojbective is to identify...
Answer:
C Thats my honest answer. To eliminate the pain you have to find out where it is. Peace.
Korey at Yahoo! Answers Mark as irrelevant Undo
When choice and responsibility are proportionally linked, that means that to whatever extent I have a choice about something, I am responsible for the outcome or consequence of that choice. And to whatever extent I am held responsible for any sort of...
Answer:
My answer is based on an assumption of free will. I do this because the vast majority of people believe...
Carl Grant at Quora Mark as irrelevant Undo
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