Is Integer Factorization Harder Than RSA Factorization?

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Is the integer factorization problem harder than RSA factorization: $n = pq$?

This is a cross-post from math.stackexchange. Let FACT denote the integer factoring problem: given $n \in \mathbb{N},$ find primes $p_i \in \mathbb{N},$ and integers $e_i \in \mathbb{N},$ such that $n = \prod_{i=0}^{k} p_{i}^{e_i}.$ Let RSA denote the special case of factoring problem where $n = pq$ and $p,q$ are primes. That is, given $n$ find primes $p,q$ or NONE if there is no such factorization. Clearly, RSA is an instance of FACT. Is FACT harder than RSA? Given an oracle that solves RSA...

Answer:

I found this paper entitled Breaking RSA May Be Easier Than Factoring. They argue that computing $e...

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user17 at Theoretical Computer Science Mark as irrelevant Undo

Other solutions

Could there be encryption standards that rest on an NP-hard problem other than integer factorization?

Similar to how RSA is secure because of the difficulty of integer factorization, could there be an encryption standard that's secure based on, say, travelling salesman or any other hard problem?

Answer:

There is no cryptosystem whose security is known to be equivalent to an NP-hard problem.  See Are the...

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Michael Hamburg at Quora Mark as irrelevant Undo

Provide the prime factorization for the integer: 3,861?

Provide the prime factorization for the integer: 3,861

Answer:

3,861 = 3^3 * 11 * 13 ------ Ideas: If the sum of all digits is a multiple of 3, then 3 is a factor.

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Alexis at Yahoo! Answers Mark as irrelevant Undo

Show that all of the powers in the prime power factorization of an integer n are even if n is a perfect square?

show that all of the powers in the prime power factorization of an integer n are even if and only if n is a perfect square

Answer:

Well, this follows pretty immediately from the following two facts: (i) (x^m)^n = x^(mn), and (ii) ...

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liberal g at Yahoo! Answers Mark as irrelevant Undo

Square roots of primes are irrational without unique factorization?

Does anybody know how to show that the square root of a prime number is irrational WITHOUT using unique factorization (the fundamental theorem of arithmetic)? I have a test covering material of this nature tomorrow. This was a homework problem (except...

Answer:

Using a somewhat different approach, we can prove a general result: If p and q are positive integers...

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Answer:

The prime factorization problem is in the NP class, but we don't know if it is NP-hard. In other words...

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Franck Dernoncourt at Quora Mark as irrelevant Undo

Whats wrong with my prime factorization C program?

my program works well but the only problem is in never outputs hte number 2. when i enter the integer 18 its supposed to spit out the prime factorization which is 2 3 3 but it gives me 3 3. whats wrong... #include<stdio.h> int main() { while(3...

Answer:

There is a much easy prime factor. http://cquestionbank.blogspot.in/2008/01/write-c-program-to-find...

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Nana at Yahoo! Answers Mark as irrelevant Undo

What is wrong with my c program? prime factorization?

my program works well but the only problem is in never outputs hte number 2. when i enter the integer 18 its supposed to spit out the prime factorization which is 2 3 3 but it gives me 3 3. whats wrong... #include<stdio.h> int main() { while(3...

Answer:

Try this though it is crude #include<stdio.h> #include<stdlib.h> int main() { int i,n,rn...

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Prime factorization problem?

suppose n is a positive integer with the following properties: n/24 is divisible by 10 but not 20 n/15 is divisible by 6 but not 18 n is not divisible by 35, 100, or any prime number with 2 or more digits what is the prime factorization of n? please...

Answer:

First constraint tells us that n has factors 2,2,2,3 (since n/24 is an integer), as well as 2,5 but...

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Jeorn at Yahoo! Answers Mark as irrelevant Undo

Answer:

[ 2^12 - 1 ] [ 2^12 + 1 ] [ 2^6 - 1 ] [ 2^6 + 1 ] [ 2^12 + 1 ] [ 2^3 - 1 ] [ 2^3 + 1 ] [ 2^6 + 1 ] ...

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a a at Yahoo! Answers Mark as irrelevant Undo

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