How to calculate molality with density and molarity?
Let’s learn how to calculate molality with density and molarity. The most accurate or helpful solution is served by eHow old.
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Answer:
Molality and molarity are measures of a solution's concentration. Both describe concentration in terms...
Ryan Menezes at eHow old Mark as irrelevant Undo
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Calculate the molality of HCl from the following data: Formula weight(amu) = 36.465 Density of solution (g/mL) = 1.19 Weight % = 37.2 Molarity = 12.1 moles solute/L solution I think the molality should end up being 6.02 moles solute/kg solvent but i...
Answer:
The weight percent will help you more here, though you can get it from density and molarity. From weight...
a zany lark at Yahoo! Answers Mark as irrelevant Undo
this problem is giving me trouble: What is the molality of NaCl in a solution that is 4.000 M NaCl, with a density of 1.44 g mL-1? Thanks!
Answer:
let there be 1 L of soution... molarity of NaCl = no. of moles of NaCl/volume of solution in litres...
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Answer:
The mole fraction, molarity and molality of NH3 if it is in a solution composed of 30.6 g NH3 in 81...
Rufus Brown at ChaCha Mark as irrelevant Undo
Answer:
This looks like chemistry homework. you won't learn if you don't do it on your own!
ChaCha Mark as irrelevant Undo
Answer:
Molarity is moles divided by liters.(n/L) Molality is moles divided by kilograms.(n/kg) Mole fraction...
Kris at Yahoo! Answers Mark as irrelevant Undo
A solution containing 66.0 g of acetone, C3H6O, and 46.0 g of water has a density of 0.926 g/mL. Calculate the mole fraction, molality and molarity of water in this solution. Help!
Answer:
(66.0 g acetone) / (58.08 g C3H6O/mol) = 1.1364 mol acetone (46.0 g H2O) / (18.01532 g H2O/mol) = 2...
W4FOSEJ734IXIF7EZX43MPZL2Q at Yahoo! Answers Mark as irrelevant Undo
quick question... calculate the molarity and the molality of an NH3 solution made up of 30.0g of NH3 in 70.0g of water. The density of the solution is 0.982g/ml it would be great if you could post the steps on how you did it as well. please and thank...
Answer:
The molarity is 0.02 mol/L. The equation for molarity is moles of solute/ volume of solvent in liters...
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B is a part of a, which is what I really need help on. a) A solution of phosphoric acid was made by dissolving 10.5 g of H3PO4 in 100.0mL of water. The resulting volume was 104mL. Calculate the molarity of this solution. 1.03M b) Assuming the density...
Answer:
hi!! a) 1.03 you are correct there........ :) b) molality = amount of solute / mass of solvent molality...
jason at Yahoo! Answers Mark as irrelevant Undo
a) A solution of phosphoric acid was made by dissolving 10.5 g of H3PO4 in 100.0mL of water. The resulting volume was 104mL. Calculate the molarity of this solution. b) Assuming the density of water is 1.00g/mL, calculate the molality of the solution...
Answer:
The molar mass of H3PO4 is 98.0 g/mol so 10.5 g 0.1071mol; this is in 0.104 L of water, so the molarity...
jason at Yahoo! Answers Mark as irrelevant Undo
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